What is the answer to (x+2)/(x^2-3x)=0 ?

The answer to (x+2)/(x^2-3x)=0 is x=-2

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(x+2)/(x^2-3x)=0

\frac{x + 2}{x ^{2} - 3 x} = 0

x = - 2

Solution steps

\frac{x + 2}{x ^{2} - 3 x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x + 2 = 0

Move

2

to the right side

x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 3, x = 0

Combine undefined points with solutions:

x = - 2

- 3 = \frac{2 x - 1}{1 - 3 x}

x - \frac{3 x + 5}{x + 1} = \frac{2 x}{x + 1}

\frac{3 x + 25}{x + 7} - 5 = \frac{3}{x}

\frac{x + 3}{- 4 x} = \frac{x - 1}{- 4}

\frac{2 x}{x - 1} = \frac{5}{x - 3}