What is the answer to 1+3/(x-1)=(x+5)/(x^2-1) ?

The answer to 1+3/(x-1)=(x+5)/(x^2-1) is x=-3

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1+3/(x-1)=(x+5)/(x^2-1)

1 + \frac{3}{x - 1} = \frac{x + 5}{x ^{2} - 1}

x = - 3

Solution steps

1 + \frac{3}{x - 1} = \frac{x + 5}{x ^{2} - 1}

Multiply by LCM

(x - 1) (x + 1) + 3 (x + 1) = x + 5

Solve

(x - 1) (x + 1) + 3 (x + 1) = x + 5 : x = 1, x = - 3

x = 1, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = 1, x = - 1

Since the equation is undefined for:

1

x = - 3

\frac{4}{x - 13} = \frac{9}{x + 13}

\frac{1}{x} - \frac{2}{x + 1} = \frac{3}{6 x}

2 x - \frac{2}{x} = 0

- 1 - \frac{5}{x} = - 6 x

\frac{3}{x + 1} - \frac{1}{x ^{2} - 1} = 0

What is the answer to 1+3/(x-1)=(x+5)/(x^2-1) ?
The answer to 1+3/(x-1)=(x+5)/(x^2-1) is x=-3
Solve for x: 1+3/(x-1)=(x+5)/(x^2-1)
The solution is x=-3