What is the answer to (x^2+4)/(x-1)= 5/(x-1) ?

The answer to (x^2+4)/(x-1)= 5/(x-1) is x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2+4)/(x-1)= 5/(x-1)

\frac{x ^{2} + 4}{x - 1} = \frac{5}{x - 1}

x = - 1

Solution steps

\frac{x ^{2} + 4}{x - 1} = \frac{5}{x - 1}

Multiply both sides by

x - 1

x^{2} + 4 = 5

Solve

x^{2} + 4 = 5 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 1

Since the equation is undefined for:

1

x = - 1

9 + \frac{x}{x - 1} = \frac{1}{x ^{2} - x}

\frac{20}{x} = x + 1

4.5 = \frac{1}{\frac{293}{x} - 1}

\frac{10}{x + 6} = 1

\frac{x + 2}{x + 3} + \frac{3}{x ^{2} + 6 x + 9} = 1

What is the answer to (x^2+4)/(x-1)= 5/(x-1) ?
The answer to (x^2+4)/(x-1)= 5/(x-1) is x=-1
Solve for x: (x^2+4)/(x-1)= 5/(x-1)
The solution is x=-1