What is the answer to 2x^{-2}=x^{-1}-1 ?

The answer to 2x^{-2}=x^{-1}-1 is x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2

Solve for x: 2x^{-2}=x^{-1}-1

The solution is x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2

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2 x^{- 2} = x^{- 1} - 1

x = \frac{1}{2} - i \frac{7}{2}, x = \frac{1}{2} + i \frac{7}{2}

Solution steps

2 x^{- 2} = x^{- 1} - 1

Refine

\frac{2}{x ^{2}} = \frac{1}{x} - 1

Multiply by LCM

2 = x - x^{2}

Solve

2 = x - x^{2} : x = \frac{1}{2} - i \frac{7}{2}, x = \frac{1}{2} + i \frac{7}{2}

x = \frac{1}{2} - i \frac{7}{2}, x = \frac{1}{2} + i \frac{7}{2}

\frac{3}{x} = \frac{1}{3} - \frac{1}{x}

1 - \frac{7}{x + 3} = \frac{7}{x ^{2} + 5 x + 6}

\frac{24}{10 + x} + 1 = \frac{24}{10 - x}

\frac{3}{y} - \frac{4}{5} = - \frac{1}{5}

- \frac{1}{5} + \frac{5}{6 x} = - \frac{1}{4 x}

What is the answer to 2x^{-2}=x^{-1}-1 ?
The answer to 2x^{-2}=x^{-1}-1 is x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2
Solve for x: 2x^{-2}=x^{-1}-1
The solution is x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2