What is the answer to 1/(x+2)+4/(x^2-4)=1 ?

The answer to 1/(x+2)+4/(x^2-4)=1 is x=3

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1/(x+2)+4/(x^2-4)=1

\frac{1}{x + 2} + \frac{4}{x ^{2} - 4} = 1

x = 3

Solution steps

\frac{1}{x + 2} + \frac{4}{x ^{2} - 4} = 1

Multiply by LCM

x + 2 = (x + 2) (x - 2)

Solve

x + 2 = (x + 2) (x - 2) : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = - 2, x = 2

Since the equation is undefined for:

- 2

x = 3

4 = \frac{x ^{2}}{x - 1}

\frac{2 x}{3 x + 5} = \frac{3}{x + 4}

a, \frac{1}{a} + \frac{1}{b} = c

\frac{5 x + 1}{x + 2} + \frac{x - 1}{x} = 2

\frac{2}{x + 2} = \frac{4}{2}

What is the answer to 1/(x+2)+4/(x^2-4)=1 ?
The answer to 1/(x+2)+4/(x^2-4)=1 is x=3
Solve for x: 1/(x+2)+4/(x^2-4)=1
The solution is x=3