What is the answer to -3/(x^2+3x)+6= 1/(x+3) ?

The answer to -3/(x^2+3x)+6= 1/(x+3) is x= 1/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-3/(x^2+3x)+6= 1/(x+3)

- \frac{3}{x ^{2} + 3 x} + 6 = \frac{1}{x + 3}

x = \frac{1}{6}

Decimal Notation

x = 0.16666 \dots

Solution steps

- \frac{3}{x ^{2} + 3 x} + 6 = \frac{1}{x + 3}

Multiply by LCM

- 3 + 6 x (x + 3) = x

Solve

- 3 + 6 x (x + 3) = x : x = \frac{1}{6}, x = - 3

x = \frac{1}{6}, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = 0

Since the equation is undefined for:

- 3

x = \frac{1}{6}

x - \frac{2 x + 3}{x + 5} = \frac{7}{x + 5}

2 = \frac{x + 2}{x - 3}

6 x + 9 = \frac{13}{5 - x}

x + \frac{3}{x + 3} = \frac{7}{x + 3}

\frac{1}{x + 4} - \frac{1}{x + 5} = \frac{1}{12}

What is the answer to -3/(x^2+3x)+6= 1/(x+3) ?
The answer to -3/(x^2+3x)+6= 1/(x+3) is x= 1/6
Solve for x: -3/(x^2+3x)+6= 1/(x+3)
The solution is x= 1/6