What is the answer to 1+2/(x-3)= 5/(x^2-9) ?

The answer to 1+2/(x-3)= 5/(x^2-9) is x=2,x=-4

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1+2/(x-3)= 5/(x^2-9)

1 + \frac{2}{x - 3} = \frac{5}{x ^{2} - 9}

x = 2, x = - 4

Solution steps

1 + \frac{2}{x - 3} = \frac{5}{x ^{2} - 9}

Multiply by LCM

(x - 3) (x + 3) + 2 (x + 3) = 5

Solve

(x - 3) (x + 3) + 2 (x + 3) = 5 : x = 2, x = - 4

x = 2, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = 3, x = - 3

Combine undefined points with solutions:

x = 2, x = - 4

2 x^{- 3} = 54

3 x - \frac{2}{x} = - 1

\frac{x ^{2}}{x - 1} = \frac{x ^{2} - 16}{x + 4}

r, S = \frac{1}{1 - r}

p, x = \frac{500}{p + 3}

What is the answer to 1+2/(x-3)= 5/(x^2-9) ?
The answer to 1+2/(x-3)= 5/(x^2-9) is x=2,x=-4
Solve for x: 1+2/(x-3)= 5/(x^2-9)
The solution is x=2,x=-4