What is the answer to (3x-2)/(2x+3)=(3x-1)/(2x+1) ?

The answer to (3x-2)/(2x+3)=(3x-1)/(2x+1) is x= 1/8

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(3x-2)/(2x+3)=(3x-1)/(2x+1)

\frac{3 x - 2}{2 x + 3} = \frac{3 x - 1}{2 x + 1}

x = \frac{1}{8}

Decimal Notation

x = 0.125

Solution steps

\frac{3 x - 2}{2 x + 3} = \frac{3 x - 1}{2 x + 1}

Cross multiply

6 x^{2} - x - 2 = 6 x^{2} + 7 x - 3

Move

2

to the right side

6 x^{2} - x = 6 x^{2} + 7 x - 1

Subtract

6 x^{2} + 7 x

from both sides

6 x^{2} - x - (6 x^{2} + 7 x) = 6 x^{2} + 7 x - 1 - (6 x^{2} + 7 x)

Simplify

- 8 x = - 1

Divide both sides by

- 8

x = \frac{1}{8}

Verify Solutions

Find undefined (singularity) points:

x = - \frac{3}{2}, x = - \frac{1}{2}

Combine undefined points with solutions:

x = \frac{1}{8}

\frac{77770}{110 + x} = 708

\frac{6}{x + 5} = \frac{8}{x}

\frac{1}{x - 1} - 3 = \frac{x}{x - 1}

\frac{6}{x - 1} = \frac{3}{x + 1}

\frac{12}{x} + x - 8 = 0

What is the answer to (3x-2)/(2x+3)=(3x-1)/(2x+1) ?
The answer to (3x-2)/(2x+3)=(3x-1)/(2x+1) is x= 1/8
Solve for x: (3x-2)/(2x+3)=(3x-1)/(2x+1)
The solution is x= 1/8