What is the answer to 5/(x^2-1)= 1/(x-1) ?

The answer to 5/(x^2-1)= 1/(x-1) is x=4

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5/(x^2-1)= 1/(x-1)

\frac{5}{x ^{2} - 1} = \frac{1}{x - 1}

x = 4

Solution steps

\frac{5}{x ^{2} - 1} = \frac{1}{x - 1}

Cross multiply

5 (x - 1) = x^{2} - 1

Solve

5 (x - 1) = x^{2} - 1 : x = 4, x = 1

x = 4, x = 1

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 1

Since the equation is undefined for:

1

x = 4

6 + \frac{4 x}{x - 1} = - 8 x

\frac{x + 2}{3} = \frac{4}{x - 2}

\frac{5}{6} = \frac{15}{x - 3}

x - \frac{7}{x + 7} = \frac{x}{x + 7}

\frac{3 x - 5}{x - 1} - \frac{2 x - 5}{x - 2} = 1

What is the answer to 5/(x^2-1)= 1/(x-1) ?
The answer to 5/(x^2-1)= 1/(x-1) is x=4
Solve for x: 5/(x^2-1)= 1/(x-1)
The solution is x=4