What are the solutions to the equation (x-4)^2=33 ?

The solutions to the equation (x-4)^2=33 are x=sqrt(33)+4,x=-sqrt(33)+4

Find the zeros of (x-4)^2=33

The zeros of (x-4)^2=33 are x=sqrt(33)+4,x=-sqrt(33)+4

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(x - 4)^{2} = 33

x = 33 + 4, x = - 33 + 4

Decimal Notation

x = 9.74456 \dots, x = - 1.74456 \dots

Solution steps

(x - 4)^{2} = 33

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 33 : x = 33 + 4

Solve

x - 4 = - 33 : x = - 33 + 4

The solutions to the quadratic equation are:

x = 33 + 4, x = - 33 + 4

lo g_{3} (x - 2) < 3

\frac{2 x + 6}{x - 6} < 0

x^{2} - 10 x y + 25 y^{2}

a^{2} - 6 ab + 8 b^{2}

(\frac{1}{8})^{2}

What are the solutions to the equation (x-4)^2=33 ?
The solutions to the equation (x-4)^2=33 are x=sqrt(33)+4,x=-sqrt(33)+4
Find the zeros of (x-4)^2=33
The zeros of (x-4)^2=33 are x=sqrt(33)+4,x=-sqrt(33)+4