What is the answer to 1+2/(x+6)=(3x)/(x^2+3x-18) ?

The answer to 1+2/(x+6)=(3x)/(x^2+3x-18) is x=4

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1+2/(x+6)=(3x)/(x^2+3x-18)

1 + \frac{2}{x + 6} = \frac{3 x}{x ^{2} + 3 x - 18}

x = 4

Solution steps

1 + \frac{2}{x + 6} = \frac{3 x}{x ^{2} + 3 x - 18}

Multiply by LCM

(x + 6) (x - 3) + 2 (x - 3) = 3 x

Solve

(x + 6) (x - 3) + 2 (x - 3) = 3 x : x = 4, x = - 6

x = 4, x = - 6

Verify Solutions

Find undefined (singularity) points:

x = - 6, x = 3

Since the equation is undefined for:

- 6

x = 4

\frac{2 x}{x ^{2} - 4} = 0

\frac{9}{2} = \frac{7 x - 8}{x + 1}

\frac{15}{x} = \frac{6}{2}

0.25 = \frac{x}{0.005 + x}

\frac{x ^{2} + 9}{3 x ^{2}} = 0

What is the answer to 1+2/(x+6)=(3x)/(x^2+3x-18) ?
The answer to 1+2/(x+6)=(3x)/(x^2+3x-18) is x=4
Solve for x: 1+2/(x+6)=(3x)/(x^2+3x-18)
The solution is x=4