What is the answer to solvefor x,16=(1-x)/(x^2) ?

The answer to solvefor x,16=(1-x)/(x^2) is x=(-1+sqrt(65))/(32),x=(-1-sqrt(65))/(32)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,16=(1-x)/(x^2)

solve for

x, 16 = \frac{1 - x}{x ^{2}}

x = \frac{- 1 + 65}{32}, x = \frac{- 1 - 65}{32}

Decimal Notation

x = 0.22069 \dots, x = - 0.28319 \dots

Solution steps

16 = \frac{1 - x}{x ^{2}}

Multiply both sides by

x^{2}

16 x^{2} = 1 - x

Solve

16 x^{2} = 1 - x : x = \frac{- 1 + 65}{32}, x = \frac{- 1 - 65}{32}

x = \frac{- 1 + 65}{32}, x = \frac{- 1 - 65}{32}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{- 1 + 65}{32}, x = \frac{- 1 - 65}{32}

\frac{4}{x} - \frac{5}{x + 3} = 1

\frac{3 x - 4}{x - 5} = \frac{3 x + 6}{x + 2}

2 x - \frac{5}{x + 6} = 3 x

- \frac{6000}{T} + 9.8 = - \frac{3500}{T} + 4.5

\frac{7}{5 - x} = 0.5

What is the answer to solvefor x,16=(1-x)/(x^2) ?
The answer to solvefor x,16=(1-x)/(x^2) is x=(-1+sqrt(65))/(32),x=(-1-sqrt(65))/(32)