What is the answer to (3(y+3))/(y+1)+2=(3y+1)/(y+1) ?

The answer to (3(y+3))/(y+1)+2=(3y+1)/(y+1) is y=-5

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(3(y+3))/(y+1)+2=(3y+1)/(y+1)

\frac{3 ( y + 3 )}{y + 1} + 2 = \frac{3 y + 1}{y + 1}

y = - 5

Solution steps

\frac{3 ( y + 3 )}{y + 1} + 2 = \frac{3 y + 1}{y + 1}

Multiply both sides by

y + 1

3 (y + 3) + 2 (y + 1) = 3 y + 1

Expand

3 (y + 3) + 2 (y + 1) : 5 y + 11

5 y + 11 = 3 y + 1

Move

11

to the right side

5 y = 3 y - 10

Move

3 y

to the left side

2 y = - 10

Divide both sides by

2

y = - 5

Verify Solutions

Find undefined (singularity) points:

y = - 1

Combine undefined points with solutions:

y = - 5

\frac{12}{x ^{3}} = 0

\frac{x - 4}{5 x} = \frac{1}{5 x} + 1

x + \frac{3 x}{x - 1} = \frac{3}{x - 1}

\frac{7}{x + 1} - \frac{1}{2} = \frac{4}{3 x + 3}

\frac{8 x - 5}{2 x + 5} = 5 - \frac{3 x + 7}{3 x + 2}

What is the answer to (3(y+3))/(y+1)+2=(3y+1)/(y+1) ?
The answer to (3(y+3))/(y+1)+2=(3y+1)/(y+1) is y=-5
Solve for y: (3(y+3))/(y+1)+2=(3y+1)/(y+1)
The solution is y=-5