What is (x-4)(x+5)<(x-3)(x-2) ?

The solution to (x-4)(x+5)<(x-3)(x-2) is x< 13/3

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(x-4)(x+5)<(x-3)(x-2)

(x - 4) (x + 5) < (x - 3) (x - 2)

x < \frac{13}{3}

Interval Notation

(- \infty, \frac{13}{3})

Decimal Notation

x < 4.33333 \dots

Solution steps

(x - 4) (x + 5) < (x - 3) (x - 2)

Rewrite in standard form

3 x - 13 < 0

Move

13

to the right side

3 x < 13

Divide both sides by

3

x < \frac{13}{3}

3 (1 - 3 x) = 2 (- 4 x + 7)

27 + 3 - \frac{45}{5 + 16}

\frac{π}{3} + \frac{π}{2}

a^{2} + 6 a - 7 = 0

What is (x-4)(x+5)<(x-3)(x-2) ?
The solution to (x-4)(x+5)<(x-3)(x-2) is x< 13/3