What is the answer to 1/(x^2-x)-1/(x-1)=0 ?

The answer to 1/(x^2-x)-1/(x-1)=0 is No Solution

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1/(x^2-x)-1/(x-1)=0

\frac{1}{x ^{2} - x} - \frac{1}{x - 1} = 0

No Solution

Solution steps

\frac{1}{x ^{2} - x} - \frac{1}{x - 1} = 0

Multiply by LCM

1 - x = 0

Move

1

to the right side

- x = - 1

Divide both sides by

- 1

x = 1

Verify Solutions

Find undefined (singularity) points:

x = 1, x = 0

Since the equation is undefined for:

1

No Solution

\frac{2}{1 - x} + \frac{3}{x + 1} = \frac{1}{x}

\frac{x - 5}{3 x + 4} = \frac{5}{8}

\frac{3}{x + 5} = \frac{2}{4 - x}

\frac{5 x}{2 x - 1} + \frac{2 x}{3 x + 2} = 3

\frac{1}{x} + \frac{1}{x - 3} = \frac{2}{x - 4}

What is the answer to 1/(x^2-x)-1/(x-1)=0 ?
The answer to 1/(x^2-x)-1/(x-1)=0 is No Solution
Solve for x: 1/(x^2-x)-1/(x-1)=0
The solution is No Solution