What is the answer to (3-5x)/(x-1)=x^2+2x-3 ?

The answer to (3-5x)/(x-1)=x^2+2x-3 is x=0,x=-1

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(3-5x)/(x-1)=x^2+2x-3

\frac{3 - 5 x}{x - 1} = x^{2} + 2 x - 3

x = 0, x = - 1

Solution steps

\frac{3 - 5 x}{x - 1} = x^{2} + 2 x - 3

Multiply both sides by

x - 1

3 - 5 x = x^{2} (x - 1) + 2 x (x - 1) - 3 (x - 1)

Solve

3 - 5 x = x^{2} (x - 1) + 2 x (x - 1) - 3 (x - 1) : x = 0, x = - 1

x = 0, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 0, x = - 1

\frac{x}{x - 1} - \frac{2}{x} = \frac{1}{x - 1}

\frac{x ^{2}}{x - 10} = \frac{100}{x - 10} - 10

x - \frac{3 x + 5}{x - 10} = 5

- \frac{3}{x + 3} + 4 x = \frac{x}{x + 3}

\frac{2}{x} + 1 + \frac{1}{x} - 1 = 1

What is the answer to (3-5x)/(x-1)=x^2+2x-3 ?
The answer to (3-5x)/(x-1)=x^2+2x-3 is x=0,x=-1
Solve for x: (3-5x)/(x-1)=x^2+2x-3
The solution is x=0,x=-1