What is the answer to 4/(x^2-1)+1= x/(x+1) ?

The answer to 4/(x^2-1)+1= x/(x+1) is x=-3

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4/(x^2-1)+1= x/(x+1)

\frac{4}{x ^{2} - 1} + 1 = \frac{x}{x + 1}

x = - 3

Solution steps

\frac{4}{x ^{2} - 1} + 1 = \frac{x}{x + 1}

Multiply by LCM

x^{2} + 3 = x^{2} - x

Move

3

to the right side

x^{2} = x^{2} - x - 3

Subtract

x^{2} - x

from both sides

x^{2} - (x^{2} - x) = x^{2} - x - 3 - (x^{2} - x)

Simplify

x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 1

Combine undefined points with solutions:

x = - 3

3 t + (\frac{4 t - 2}{3 t ^{3}}) = 7

\frac{x}{x + 1} - \frac{1}{x ^{2} + x} = - 3

c, c = \frac{0.05 q ^{2} + 5 q + 500}{q}

\frac{2 x}{x ^{2} + 7} = 0

10 = \frac{1 + 7 x}{7 + x}

What is the answer to 4/(x^2-1)+1= x/(x+1) ?
The answer to 4/(x^2-1)+1= x/(x+1) is x=-3
Solve for x: 4/(x^2-1)+1= x/(x+1)
The solution is x=-3