What is the answer to 1/(x+9)+(18)/(x^2-81)=1 ?

The answer to 1/(x+9)+(18)/(x^2-81)=1 is x=10

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1/(x+9)+(18)/(x^2-81)=1

\frac{1}{x + 9} + \frac{18}{x ^{2} - 81} = 1

x = 10

Solution steps

\frac{1}{x + 9} + \frac{18}{x ^{2} - 81} = 1

Multiply by LCM

x + 9 = (x + 9) (x - 9)

Solve

x + 9 = (x + 9) (x - 9) : x = 10, x = - 9

x = 10, x = - 9

Verify Solutions

Find undefined (singularity) points:

x = - 9, x = 9

Since the equation is undefined for:

- 9

x = 10

\frac{8 x ^{8} x ^{8} x ^{8} x ^{8}}{8 x ^{8}} = 8 x

1 + \frac{x}{x - 9} = \frac{1}{x - 9}

\frac{4 x ^{3}}{x ^{4} + 27} = 0

- \frac{3}{5 y + 10} + 2 = \frac{5}{y + 2}

4 - \frac{4}{x ^{2}} = 0

What is the answer to 1/(x+9)+(18)/(x^2-81)=1 ?
The answer to 1/(x+9)+(18)/(x^2-81)=1 is x=10
Solve for x: 1/(x+9)+(18)/(x^2-81)=1
The solution is x=10