What is the answer to (7x-1)/(x^2+9)=1 ?

The answer to (7x-1)/(x^2+9)=1 is x=5,x=2

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(7x-1)/(x^2+9)=1

\frac{7 x - 1}{x ^{2} + 9} = 1

x = 5, x = 2

Solution steps

\frac{7 x - 1}{x ^{2} + 9} = 1

Multiply both sides by

x^{2} + 9

7 x - 1 = x^{2} + 9

Solve

7 x - 1 = x^{2} + 9 : x = 5, x = 2

x = 5, x = 2

\frac{5 x}{x - 3} - 1 = - \frac{1}{x - 3}

\frac{8}{x} = \frac{x}{2}

- \frac{1}{x ^{2}} = - \frac{1}{7}

19.11969 = 19.62 x + (\frac{1.5}{3 x})^{2}

\frac{1}{5} + \frac{2}{3} = \frac{1}{x}

What is the answer to (7x-1)/(x^2+9)=1 ?
The answer to (7x-1)/(x^2+9)=1 is x=5,x=2
Solve for x: (7x-1)/(x^2+9)=1
The solution is x=5,x=2