What is the answer to 5+x^2=(x+1)(x+6) ?

The answer to 5+x^2=(x+1)(x+6) is x=-1/7

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5+x^2=(x+1)(x+6)

5 + x^{2} = (x + 1) (x + 6)

x = - \frac{1}{7}

Decimal Notation

x = - 0.14285 \dots

Solution steps

5 + x^{2} = (x + 1) (x + 6)

Expand

(x + 1) (x + 6) : x^{2} + 7 x + 6

5 + x^{2} = x^{2} + 7 x + 6

Move

5

to the right side

x^{2} = x^{2} + 7 x + 1

Subtract

x^{2} + 7 x

from both sides

x^{2} - (x^{2} + 7 x) = x^{2} + 7 x + 1 - (x^{2} + 7 x)

Simplify

- 7 x = 1

Divide both sides by

- 7

x = - \frac{1}{7}

m^{4} + m^{2} - 2

3 x^{2} + 26 x + 35

14 b^{2} - 2 + 3 b = 0

8 + 7 n = 6 n + 2 n

- 8 x + 4 > 44

What is the answer to 5+x^2=(x+1)(x+6) ?
The answer to 5+x^2=(x+1)(x+6) is x=-1/7
Solve for x: 5+x^2=(x+1)(x+6)
The solution is x=-1/7