What is the answer to (x^2}{16}=1+\frac{3/(4x))/9 ?

The answer to (x^2}{16}=1+\frac{3/(4x))/9 is x\approx-0.08336…,x\approx-3.95766…,x\approx 4.04103…

Solve for x: (x^2}{16}=1+\frac{3/(4x))/9

The solution is x\approx-0.08336…,x\approx-3.95766…,x\approx 4.04103…

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\frac{x ^{2}}{16} = 1 + \frac{\frac{3}{4 x}}{9}

x \approx - 0.08336 \dots, x \approx - 3.95766 \dots, x \approx 4.04103 \dots

Solution steps

\frac{x ^{2}}{16} = 1 + \frac{\frac{3}{4 x}}{9}

Multiply by LCM

3 x^{3} = 48 x + 4

Solve

3 x^{3} = 48 x + 4 : x \approx - 0.08336 \dots, x \approx - 3.95766 \dots, x \approx 4.04103 \dots

x \approx - 0.08336 \dots, x \approx - 3.95766 \dots, x \approx 4.04103 \dots

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x \approx - 0.08336 \dots, x \approx - 3.95766 \dots, x \approx 4.04103 \dots

y, - \frac{y}{x} = - 1

\frac{6}{x} = x - 5

\frac{x ^{2}}{2} - \frac{x ^{2}}{x + 1} = 0

\frac{a}{9 a - 2} = \frac{1}{8}

y, x = \frac{y}{1 - y}

What is the answer to (x^2}{16}=1+\frac{3/(4x))/9 ?
The answer to (x^2}{16}=1+\frac{3/(4x))/9 is x\approx-0.08336…,x\approx-3.95766…,x\approx 4.04103…
Solve for x: (x^2}{16}=1+\frac{3/(4x))/9
The solution is x\approx-0.08336…,x\approx-3.95766…,x\approx 4.04103…