What is the answer to (x^2)/(3-x)=(2x)/(3-x) ?

The answer to (x^2)/(3-x)=(2x)/(3-x) is x=2,x=0

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(x^2)/(3-x)=(2x)/(3-x)

\frac{x ^{2}}{3 - x} = \frac{2 x}{3 - x}

x = 2, x = 0

Solution steps

\frac{x ^{2}}{3 - x} = \frac{2 x}{3 - x}

Multiply both sides by

3 - x

x^{2} = 2 x

Solve

x^{2} = 2 x : x = 2, x = 0

x = 2, x = 0

Verify Solutions

Find undefined (singularity) points:

x = 3

Combine undefined points with solutions:

x = 2, x = 0

\frac{x}{x + 1} + 6 = \frac{1}{x ^{2} + x}

9 x + 1 = \frac{8}{x}

\frac{2 x}{x - 2} = 9 + \frac{25 x ^{2}}{x - 2}

\frac{x}{x + 1} = 2 (x + 1)^{2}

\frac{1}{x - 3} + \frac{1}{x + 1} = \frac{6}{5}

What is the answer to (x^2)/(3-x)=(2x)/(3-x) ?
The answer to (x^2)/(3-x)=(2x)/(3-x) is x=2,x=0
Solve for x: (x^2)/(3-x)=(2x)/(3-x)
The solution is x=2,x=0