What is the answer to 1-2/(x+1)=(2x)/(x^2+3x+2) ?

The answer to 1-2/(x+1)=(2x)/(x^2+3x+2) is x=2

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1-2/(x+1)=(2x)/(x^2+3x+2)

1 - \frac{2}{x + 1} = \frac{2 x}{x ^{2} + 3 x + 2}

x = 2

Solution steps

1 - \frac{2}{x + 1} = \frac{2 x}{x ^{2} + 3 x + 2}

Multiply by LCM

(x + 1) (x + 2) - 2 (x + 2) = 2 x

Solve

(x + 1) (x + 2) - 2 (x + 2) = 2 x : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = - 2

Since the equation is undefined for:

- 1

x = 2

2 x + \frac{3}{x + 2} = 1

\frac{1}{x} = \frac{1}{5} + \frac{3}{2 x}

x, (f - g) (x) = \frac{( x ^{2} + 2 x - 1 )}{x}

6 - \frac{35}{x} + \frac{36}{x ^{2}} = 0

\frac{1}{x - 2} + \frac{3}{x + 3} = 6

What is the answer to 1-2/(x+1)=(2x)/(x^2+3x+2) ?
The answer to 1-2/(x+1)=(2x)/(x^2+3x+2) is x=2
Solve for x: 1-2/(x+1)=(2x)/(x^2+3x+2)
The solution is x=2