What is the answer to (x+2)/(x+3)-1= 1/(3-2x-x^2) ?

The answer to (x+2)/(x+3)-1= 1/(3-2x-x^2) is x=2

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(x+2)/(x+3)-1= 1/(3-2x-x^2)

\frac{x + 2}{x + 3} - 1 = \frac{1}{3 - 2 x - x ^{2}}

x = 2

Solution steps

\frac{x + 2}{x + 3} - 1 = \frac{1}{3 - 2 x - x ^{2}}

Multiply by LCM

- x + 1 = - 1

Move

1

to the right side

- x = - 2

Divide both sides by

- 1

x = 2

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = 1

Combine undefined points with solutions:

x = 2

\frac{9}{5} = \frac{10}{9 x}

x, \frac{a + b}{x} = z

x, \frac{4}{x + 4} = \frac{x}{3}

- \frac{1}{x ^{2}} = - \frac{1}{24}

\frac{2}{x} = \frac{3}{4}

What is the answer to (x+2)/(x+3)-1= 1/(3-2x-x^2) ?
The answer to (x+2)/(x+3)-1= 1/(3-2x-x^2) is x=2
Solve for x: (x+2)/(x+3)-1= 1/(3-2x-x^2)
The solution is x=2