What is the answer to x/(x-3)-(x+5)/(x^2-9)=1 ?

The answer to x/(x-3)-(x+5)/(x^2-9)=1 is x=-2

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x/(x-3)-(x+5)/(x^2-9)=1

\frac{x}{x - 3} - \frac{x + 5}{x ^{2} - 9} = 1

x = - 2

Solution steps

\frac{x}{x - 3} - \frac{x + 5}{x ^{2} - 9} = 1

Multiply by LCM

x^{2} + 2 x - 5 = x^{2} - 9

Move

5

to the right side

x^{2} + 2 x = x^{2} - 4

Move

x^{2}

to the left side

2 x = - 4

Divide both sides by

2

x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 3, x = - 3

Combine undefined points with solutions:

x = - 2

\frac{1}{x} + \frac{1}{x - 2} = \frac{1}{4}

\frac{x - 1}{4} + \frac{5}{x + 3} = \frac{7}{2}

12 (2 - x) = \frac{8}{3 \times ( 1 - 2 x )}

c = \frac{5 d + 4 w}{2 w}

a, p = \frac{f}{a}

What is the answer to x/(x-3)-(x+5)/(x^2-9)=1 ?
The answer to x/(x-3)-(x+5)/(x^2-9)=1 is x=-2
Solve for x: x/(x-3)-(x+5)/(x^2-9)=1
The solution is x=-2