What is the answer to 1+1/(x-4)= 4/(x^2-4x) ?

The answer to 1+1/(x-4)= 4/(x^2-4x) is x=-1

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1+1/(x-4)= 4/(x^2-4x)

1 + \frac{1}{x - 4} = \frac{4}{x ^{2} - 4 x}

x = - 1

Solution steps

1 + \frac{1}{x - 4} = \frac{4}{x ^{2} - 4 x}

Multiply by LCM

x (x - 4) + x = 4

Solve

x (x - 4) + x = 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 4, x = 0

Since the equation is undefined for:

4

x = - 1

x - \frac{2 x + 7}{x - 3} = \frac{x}{x - 3}

\frac{5}{a} + \frac{3}{4} = \frac{1}{a}

0 = 1 - \frac{1}{x - 3}

\frac{6 - 5 + 14}{n \times 2} = 15

\frac{x ^{2} - x - 6}{x - 3} = 5 x - 1

What is the answer to 1+1/(x-4)= 4/(x^2-4x) ?
The answer to 1+1/(x-4)= 4/(x^2-4x) is x=-1
Solve for x: 1+1/(x-4)= 4/(x^2-4x)
The solution is x=-1