What are the solutions to the equation 120=16t^2 ?

The solutions to the equation 120=16t^2 are t=sqrt(15/2),t=-sqrt(15/2)

Find the zeros of 120=16t^2

The zeros of 120=16t^2 are t=sqrt(15/2),t=-sqrt(15/2)

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120 = 16 t^{2}

t = \frac{15}{2}, t = - \frac{15}{2}

Solution steps

120 = 16 t^{2}

Switch sides

16 t^{2} = 120

Divide both sides by

16

t^{2} = \frac{15}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{15}{2}, t = - \frac{15}{2}

\frac{2 ^{- 1}}{- 1}

2^{8} - 1

- a + 2 = 1

2 x^{2} - 5 x + 1 = 4

8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1

What are the solutions to the equation 120=16t^2 ?
The solutions to the equation 120=16t^2 are t=sqrt(15/2),t=-sqrt(15/2)
Find the zeros of 120=16t^2
The zeros of 120=16t^2 are t=sqrt(15/2),t=-sqrt(15/2)