What is the answer to 4/(x-1)-4/(x^2-x)=2 ?

The answer to 4/(x-1)-4/(x^2-x)=2 is x=2

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4/(x-1)-4/(x^2-x)=2

\frac{4}{x - 1} - \frac{4}{x ^{2} - x} = 2

x = 2

Solution steps

\frac{4}{x - 1} - \frac{4}{x ^{2} - x} = 2

Multiply by LCM

4 x - 4 = 2 x (x - 1)

Solve

4 x - 4 = 2 x (x - 1) : x = 2, x = 1

x = 2, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 1, x = 0

Since the equation is undefined for:

1

x = 2

\frac{x - 1}{x - 3} = \frac{2}{x - 3}

\frac{2 x}{2 x + 3} + \frac{6}{4 x + 6} = 5

\frac{2 x}{x - 12} = \frac{- 2}{x + 3}

2 = \frac{16}{e}

\frac{3 x + 6}{3} - \frac{4 x}{x - 3} = x

What is the answer to 4/(x-1)-4/(x^2-x)=2 ?
The answer to 4/(x-1)-4/(x^2-x)=2 is x=2
Solve for x: 4/(x-1)-4/(x^2-x)=2
The solution is x=2