What is the answer to roots (x^{10}-m^{10})/(x^2+m^2) ?

The answer to roots (x^{10}-m^{10})/(x^2+m^2) is x=m,x=-m

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roots (x^{10}-m^{10})/(x^2+m^2)

roots

\frac{x ^{10} - m ^{10}}{x ^{2} + m ^{2}}

x = m, x = - m

Solution steps

\frac{x ^{10} - m ^{10}}{x ^{2} + m ^{2}}

The roots are the intercepts with the x-axis

(y = 0)

\frac{x ^{10} - m ^{10}}{x ^{2} + m ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{10} - m^{10} = 0

Solve

x^{10} - m^{10} = 0 : x = m, x = - m

x = m, x = - m

\frac{x ^{2} + 1}{x} = \frac{4}{3}

x, \frac{2}{x} = 1.32588

\frac{x ^{2}}{x - 6} = \frac{36}{x - 6}

\frac{5 - x}{x - 2} + \frac{3}{x ^{2} - 4} = 2

\frac{x - 3}{x - 1} = 2

What is the answer to roots (x^{10}-m^{10})/(x^2+m^2) ?
The answer to roots (x^{10}-m^{10})/(x^2+m^2) is x=m,x=-m