What is the answer to 1/(x^2-x)-1/(x-1)=-2 ?

The answer to 1/(x^2-x)-1/(x-1)=-2 is x= 1/2

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1/(x^2-x)-1/(x-1)=-2

\frac{1}{x ^{2} - x} - \frac{1}{x - 1} = - 2

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

\frac{1}{x ^{2} - x} - \frac{1}{x - 1} = - 2

Multiply by LCM

1 - x = - 2 x (x - 1)

Solve

1 - x = - 2 x (x - 1) : x = \frac{1}{2}, x = 1

x = \frac{1}{2}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 1, x = 0

Since the equation is undefined for:

1

x = \frac{1}{2}

\frac{2}{y} = \frac{1}{y - 2} - 3

y, x = \frac{y - 1}{y + 1}

1 + \frac{x - 2}{x + 1} = 3 x - 5

\frac{x}{2} + \frac{4}{x} = 3

1 - \frac{7}{x ^{2}} = 0

What is the answer to 1/(x^2-x)-1/(x-1)=-2 ?
The answer to 1/(x^2-x)-1/(x-1)=-2 is x= 1/2
Solve for x: 1/(x^2-x)-1/(x-1)=-2
The solution is x= 1/2