What is the answer to 3/(x+1)= 9/(x^2-3x-4) ?

The answer to 3/(x+1)= 9/(x^2-3x-4) is x=7

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3/(x+1)= 9/(x^2-3x-4)

\frac{3}{x + 1} = \frac{9}{x ^{2} - 3 x - 4}

x = 7

Solution steps

\frac{3}{x + 1} = \frac{9}{x ^{2} - 3 x - 4}

Cross multiply

3 (x^{2} - 3 x - 4) = (x + 1) \cdot 9

Solve

3 (x^{2} - 3 x - 4) = (x + 1) \cdot 9 : x = - 1, x = 7

x = - 1, x = 7

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 4

Since the equation is undefined for:

- 1

x = 7

\frac{r}{6} + \frac{r - 1}{r} = \frac{7}{6}

\frac{2 x}{x - 5} = \frac{2}{3}

\frac{x - 2}{3 x} + \frac{1}{2} = 1

x + \frac{6}{x} = 4

1 + \frac{5 x}{x - 1} = \frac{5}{x - 1}

What is the answer to 3/(x+1)= 9/(x^2-3x-4) ?
The answer to 3/(x+1)= 9/(x^2-3x-4) is x=7
Solve for x: 3/(x+1)= 9/(x^2-3x-4)
The solution is x=7