What is the answer to 1/(3x+3)= 1/6-2/(x+1) ?

The answer to 1/(3x+3)= 1/6-2/(x+1) is x=13

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1/(3x+3)= 1/6-2/(x+1)

\frac{1}{3 x + 3} = \frac{1}{6} - \frac{2}{x + 1}

x = 13

Solution steps

\frac{1}{3 x + 3} = \frac{1}{6} - \frac{2}{x + 1}

Multiply by LCM

2 = x - 11

Switch sides

x - 11 = 2

Move

11

to the right side

x = 13

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = 13

\frac{x - 9}{3 x - 1} = \frac{x - 9}{x + 33}

- 6 = \frac{e ^{\frac{- 1 + C}{- 1}}}{x}

\frac{3 x - 26}{7} = \frac{- 5}{x}

- \frac{1}{x ^{2} + 1} = 0

\frac{9}{2 x} = \frac{7}{2 x} + 2

What is the answer to 1/(3x+3)= 1/6-2/(x+1) ?
The answer to 1/(3x+3)= 1/6-2/(x+1) is x=13
Solve for x: 1/(3x+3)= 1/6-2/(x+1)
The solution is x=13