What is the answer to (-3)/(4x+3)= N/(4x^2-13x-12) ?

The answer to (-3)/(4x+3)= N/(4x^2-13x-12) is x=-N/3+4

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(-3)/(4x+3)= N/(4x^2-13x-12)

\frac{- 3}{4 x + 3} = \frac{N}{4 x ^{2} - 13 x - 12}

x = - \frac{N}{3} + 4

Solution steps

\frac{- 3}{4 x + 3} = \frac{N}{4 x ^{2} - 13 x - 12}

Cross multiply

- 3 (4 x^{2} - 13 x - 12) = (4 x + 3) N

Solve

- 3 (4 x^{2} - 13 x - 12) = (4 x + 3) N : x = - \frac{3}{4}, x = - \frac{N}{3} + 4

x = - \frac{3}{4}, x = - \frac{N}{3} + 4

Verify Solutions

Find undefined (singularity) points:

x = - \frac{3}{4}, x = 4

Since the equation is undefined for:

- \frac{3}{4}

x = - \frac{N}{3} + 4

\frac{3 x}{x - 3} + 2 = \frac{3 x - 1}{x + 3}

\frac{x}{x + 3} + 2 = \frac{9}{x ^{2} + 3 x}

\frac{2 x}{x - 2} = - \frac{30}{x ^{2} - 10 x + 16}

y, \frac{2 x}{y} = \frac{2 y}{x}

x - \frac{3 x + 5}{x - 9} = 2 x

What is the answer to (-3)/(4x+3)= N/(4x^2-13x-12) ?
The answer to (-3)/(4x+3)= N/(4x^2-13x-12) is x=-N/3+4