What is the answer to (x^2-1)/(x^2-2x+1)=0 ?

The answer to (x^2-1)/(x^2-2x+1)=0 is x=-1

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(x^2-1)/(x^2-2x+1)=0

\frac{x ^{2} - 1}{x ^{2} - 2 x + 1} = 0

x = - 1

Solution steps

\frac{x ^{2} - 1}{x ^{2} - 2 x + 1} = 0

Simplify

\frac{x ^{2} - 1}{x ^{2} - 2 x + 1} : \frac{x + 1}{x - 1}

\frac{x + 1}{x - 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x + 1 = 0

Move

1

to the right side

x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = - 1

\frac{x - 2}{3 x} = \frac{1}{3 x} + 2

\frac{3}{x} = 3

\frac{x - 3}{x + 3} = \frac{x - 4}{x + 4}

\frac{2}{x + 1} - \frac{1}{4} = \frac{1}{5 x + 5}

\frac{x ^{2}}{x + 3} = \frac{9}{x + 3}

What is the answer to (x^2-1)/(x^2-2x+1)=0 ?
The answer to (x^2-1)/(x^2-2x+1)=0 is x=-1
Solve for x: (x^2-1)/(x^2-2x+1)=0
The solution is x=-1