What is the answer to (x^2+1)/(x^2-1)= 13/12 ?

The answer to (x^2+1)/(x^2-1)= 13/12 is x=5,x=-5

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(x^2+1)/(x^2-1)= 13/12

\frac{x ^{2} + 1}{x ^{2} - 1} = \frac{13}{12}

x = 5, x = - 5

Solution steps

\frac{x ^{2} + 1}{x ^{2} - 1} = \frac{13}{12}

Cross multiply

(x^{2} + 1) \cdot 12 = (x^{2} - 1) \cdot 13

Solve

(x^{2} + 1) \cdot 12 = (x^{2} - 1) \cdot 13 : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions

Find undefined (singularity) points:

x = 1, x = - 1

Combine undefined points with solutions:

x = 5, x = - 5

\frac{t ^{3}}{6} + \frac{1}{2 t} = 2.91

\frac{4}{( 2 x + 3 )} = \frac{3}{( x - 3 )}

y, x = \frac{y}{y - 1}

\frac{x - 0.8}{x + 0.2} = \frac{1}{2}

5 x^{- 2} + 13 x^{- 1} = 28

What is the answer to (x^2+1)/(x^2-1)= 13/12 ?
The answer to (x^2+1)/(x^2-1)= 13/12 is x=5,x=-5
Solve for x: (x^2+1)/(x^2-1)= 13/12
The solution is x=5,x=-5