What are the solutions to the equation 25=(x+1)^2+x^2 ?

The solutions to the equation 25=(x+1)^2+x^2 are x=3,x=-4

Find the zeros of 25=(x+1)^2+x^2

The zeros of 25=(x+1)^2+x^2 are x=3,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 = (x + 1)^{2} + x^{2}

x = 3, x = - 4

Solution steps

25 = (x + 1)^{2} + x^{2}

Expand

(x + 1)^{2} + x^{2} : 2 x^{2} + 2 x + 1

25 = 2 x^{2} + 2 x + 1

Switch sides

2 x^{2} + 2 x + 1 = 25

Move

25

to the left side

2 x^{2} + 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 24) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 2}, x_{2} = \frac{- 2 - 14}{2 \cdot 2}

x = \frac{- 2 + 14}{2 \cdot 2} : 3

x = \frac{- 2 - 14}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

\frac{- 8}{4}

\frac{π}{4} + \frac{π}{12}

3 x - 4 = 20

- 2 < - z + 1 < 2

\frac{2 + - 8}{1 + - 2}

What are the solutions to the equation 25=(x+1)^2+x^2 ?
The solutions to the equation 25=(x+1)^2+x^2 are x=3,x=-4
Find the zeros of 25=(x+1)^2+x^2
The zeros of 25=(x+1)^2+x^2 are x=3,x=-4