What is the answer to solvefor y,x=(y+1)/(2y+1) ?

The answer to solvefor y,x=(y+1)/(2y+1) is y=(1-x)/(2x-1);\quad x\ne 1/2

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solvefor y,x=(y+1)/(2y+1)

solve for

y, x = \frac{y + 1}{2 y + 1}

y = \frac{1 - x}{2 x - 1}; x \neq = \frac{1}{2}

Solution steps

x = \frac{y + 1}{2 y + 1}

Multiply both sides by

2 y + 1

x (2 y + 1) = y + 1

Expand

x (2 y + 1) : 2 y x + x

2 y x + x = y + 1

Move

x

to the right side

2 y x = y + 1 - x

Move

y

to the left side

2 y x - y = 1 - x

Factor

2 y x - y : y (2 x - 1)

y (2 x - 1) = 1 - x

Divide both sides by

2 x - 1; x \neq = \frac{1}{2}

y = \frac{1 - x}{2 x - 1}; x \neq = \frac{1}{2}

\frac{3 x + 4}{2 x - 5} = \frac{5 x + 4}{2 x - 3}

\frac{x + 2}{2 x} - \frac{x}{4} = \frac{1}{2}

x + \frac{50}{x} = 27

N, 5 d + g = \frac{b}{N}

\frac{x - 4}{x + 2} = \frac{5}{x}

What is the answer to solvefor y,x=(y+1)/(2y+1) ?
The answer to solvefor y,x=(y+1)/(2y+1) is y=(1-x)/(2x-1);\quad x\ne 1/2