What is the answer to roots (s^6-n^9)/(s^6-n^6) ?

The answer to roots (s^6-n^9)/(s^6-n^6) is s=nsqrt(n),s=-nsqrt(n)

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roots (s^6-n^9)/(s^6-n^6)

roots

\frac{s ^{6} - n ^{9}}{s ^{6} - n ^{6}}

s = n n, s = - n n

Solution steps

\frac{s ^{6} - n ^{9}}{s ^{6} - n ^{6}}

The roots are the intercepts with the x-axis

(y = 0)

\frac{s ^{6} - n ^{9}}{s ^{6} - n ^{6}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

s^{6} - n^{9} = 0

Solve

s^{6} - n^{9} = 0 : s = n n, s = - n n

s = n n, s = - n n

0 = \frac{2}{x ^{3}}

y, x = \frac{x + y}{x - y}

\frac{20}{x} = 9 - x

\frac{x + a}{x - a}

\frac{1}{16} = b^{- 2}

What is the answer to roots (s^6-n^9)/(s^6-n^6) ?
The answer to roots (s^6-n^9)/(s^6-n^6) is s=nsqrt(n),s=-nsqrt(n)