What is the answer to 2/(x-2)-4/(x^2-2x)=3 ?

The answer to 2/(x-2)-4/(x^2-2x)=3 is x= 2/3

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2/(x-2)-4/(x^2-2x)=3

\frac{2}{x - 2} - \frac{4}{x ^{2} - 2 x} = 3

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

\frac{2}{x - 2} - \frac{4}{x ^{2} - 2 x} = 3

Multiply by LCM

2 x - 4 = 3 x (x - 2)

Solve

2 x - 4 = 3 x (x - 2) : x = 2, x = \frac{2}{3}

x = 2, x = \frac{2}{3}

Verify Solutions

Find undefined (singularity) points:

x = 2, x = 0

Since the equation is undefined for:

2

x = \frac{2}{3}

\frac{2}{x + 1} + \frac{3}{x} = \frac{5}{x - 2}

2 + \frac{1}{x} = 4

\frac{y ^{2}}{y + 4} = \frac{16}{y + 4}

\frac{8}{q} + 2 = \frac{q + 4}{q - 1}

\frac{1}{8} + \frac{1}{x} = \frac{1}{2}

What is the answer to 2/(x-2)-4/(x^2-2x)=3 ?
The answer to 2/(x-2)-4/(x^2-2x)=3 is x= 2/3
Solve for x: 2/(x-2)-4/(x^2-2x)=3
The solution is x= 2/3