What is the answer to solvefor y,x=(2+y)/(2-y) ?

The answer to solvefor y,x=(2+y)/(2-y) is y=-(2-2x)/(1+x);\quad x\ne-1

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solvefor y,x=(2+y)/(2-y)

solve for

y, x = \frac{2 + y}{2 - y}

y = - \frac{2 - 2 x}{1 + x}; x \neq = - 1

Solution steps

x = \frac{2 + y}{2 - y}

Multiply both sides by

2 - y

x (2 - y) = 2 + y

Expand

x (2 - y) : 2 x - y x

2 x - y x = 2 + y

Move

2 x

to the right side

- y x = 2 + y - 2 x

Move

y

to the left side

- y x - y = 2 - 2 x

Factor

- y x - y : - y (x + 1)

- y (x + 1) = 2 - 2 x

Divide both sides by

- (x + 1); x \neq = - 1

y = - \frac{2 - 2 x}{1 + x}; x \neq = - 1

y, \frac{5}{x} - \frac{1}{y} = 4

y, x = \frac{y ^{2} - 9}{8 y ^{2}}

\frac{2 ( t ^{2} - 4 )}{t ^{2} + 1} = 1

a, 1 = \frac{7}{a} + \frac{11}{b} + \frac{24}{ab}

\frac{5}{x} = \frac{3}{x - 2}

What is the answer to solvefor y,x=(2+y)/(2-y) ?
The answer to solvefor y,x=(2+y)/(2-y) is y=-(2-2x)/(1+x);\quad x\ne-1