What is the answer to (x^2-6x)/(3x-1)=(3x-4)/(1-3x) ?

The answer to (x^2-6x)/(3x-1)=(3x-4)/(1-3x) is x=-1,x=4

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(x^2-6x)/(3x-1)=(3x-4)/(1-3x)

\frac{x ^{2} - 6 x}{3 x - 1} = \frac{3 x - 4}{1 - 3 x}

x = - 1, x = 4

Solution steps

\frac{x ^{2} - 6 x}{3 x - 1} = \frac{3 x - 4}{1 - 3 x}

Cross multiply

(x^{2} - 6 x) (1 - 3 x) = (3 x - 1) (3 x - 4)

Solve

(x^{2} - 6 x) (1 - 3 x) = (3 x - 1) (3 x - 4) : x = - 1, x = 4, x = \frac{1}{3}

x = - 1, x = 4, x = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

x = \frac{1}{3}

Since the equation is undefined for:

\frac{1}{3}

x = - 1, x = 4

x - \frac{5}{x + 6} = 2 x

\frac{2 x - 5}{x - 4} = \frac{11}{x - 4}

\frac{1}{x} = \frac{1}{4} + \frac{1}{4}

\frac{5}{x + 4} = 4 + \frac{3}{x - 2}

0.2 = \frac{6 + 2 x}{12 + x}

What is the answer to (x^2-6x)/(3x-1)=(3x-4)/(1-3x) ?
The answer to (x^2-6x)/(3x-1)=(3x-4)/(1-3x) is x=-1,x=4
Solve for x: (x^2-6x)/(3x-1)=(3x-4)/(1-3x)
The solution is x=-1,x=4