What is the answer to (x^3-4x+3)/(x^4+2x-4)=0 ?

The answer to (x^3-4x+3)/(x^4+2x-4)=0 is x=1,x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

Solve for x: (x^3-4x+3)/(x^4+2x-4)=0

The solution is x=1,x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{x ^{3} - 4 x + 3}{x ^{4} + 2 x - 4} = 0

x = 1, x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

Decimal Notation

x = 1, x = 1.30277 \dots, x = - 2.30277 \dots

Solution steps

\frac{x ^{3} - 4 x + 3}{x ^{4} + 2 x - 4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{3} - 4 x + 3 = 0

Solve

x^{3} - 4 x + 3 = 0 : x = 1, x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

x = 1, x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

Verify Solutions

Find undefined (singularity) points:

x = 1.14390 \dots, x = - 1.64293 \dots

Combine undefined points with solutions:

x = 1, x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

\frac{x}{3} - \frac{6}{x} = 1

\frac{1}{15} + \frac{1}{21} = \frac{1}{x}

\frac{x + 1}{x} = 5

\frac{8}{x} - x = 4

\frac{3}{n} - \frac{1}{2} = \frac{n - 5}{n}

What is the answer to (x^3-4x+3)/(x^4+2x-4)=0 ?
The answer to (x^3-4x+3)/(x^4+2x-4)=0 is x=1,x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2
Solve for x: (x^3-4x+3)/(x^4+2x-4)=0
The solution is x=1,x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2