What is the answer to 1/(x-3)-3/(x^2-3x)=4 ?

The answer to 1/(x-3)-3/(x^2-3x)=4 is x= 1/4

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1/(x-3)-3/(x^2-3x)=4

\frac{1}{x - 3} - \frac{3}{x ^{2} - 3 x} = 4

x = \frac{1}{4}

Decimal

x = 0.25

Solution steps

\frac{1}{x - 3} - \frac{3}{x ^{2} - 3 x} = 4

Multiply by LCM

x - 3 = 4 x (x - 3)

Solve

x - 3 = 4 x (x - 3) : x = 3, x = \frac{1}{4}

x = 3, x = \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

x = 3, x = 0

Since the equation is undefined for:

3

x = \frac{1}{4}

0 = 3 x^{2} - \frac{24}{x}

\frac{x}{x - 2} - \frac{9}{2 - x} = 2

0 = 1 - \frac{16}{x ^{2}}

2 + \frac{1149984}{x ^{3}} = 66

1 - \frac{3}{2 x} = \frac{7}{4}

What is the answer to 1/(x-3)-3/(x^2-3x)=4 ?
The answer to 1/(x-3)-3/(x^2-3x)=4 is x= 1/4
Solve for x: 1/(x-3)-3/(x^2-3x)=4
The solution is x= 1/4