What is the answer to x^2=(12)/(x^2+1) ?

The answer to x^2=(12)/(x^2+1) is x=sqrt(3),x=-sqrt(3),x=2i,x=-2i

Solve for x: x^2=(12)/(x^2+1)

The solution is x=sqrt(3),x=-sqrt(3),x=2i,x=-2i

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x^{2} = \frac{12}{x ^{2} + 1}

x = 3, x = - 3, x = 2 i, x = - 2 i

Solution steps

x^{2} = \frac{12}{x ^{2} + 1}

Multiply both sides by

x^{2} + 1

x^{2} (x^{2} + 1) = 12

Solve

x^{2} (x^{2} + 1) = 12 : x = 3, x = - 3, x = 2 i, x = - 2 i

x = 3, x = - 3, x = 2 i, x = - 2 i

P, T = \frac{A - P}{P x}

\frac{8}{( x + 2 ) ^{3}} = 0

\frac{3}{x} + \frac{2 x}{x + 2} = - \frac{1}{x}

\frac{3 w + 7}{w} = \frac{w - 9}{w - 1}

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What is the answer to x^2=(12)/(x^2+1) ?
The answer to x^2=(12)/(x^2+1) is x=sqrt(3),x=-sqrt(3),x=2i,x=-2i
Solve for x: x^2=(12)/(x^2+1)
The solution is x=sqrt(3),x=-sqrt(3),x=2i,x=-2i