What is the answer to 1-7/(x-2)= 7/(x^2-5x+6) ?

The answer to 1-7/(x-2)= 7/(x^2-5x+6) is x=10

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1-7/(x-2)= 7/(x^2-5x+6)

1 - \frac{7}{x - 2} = \frac{7}{x ^{2} - 5 x + 6}

x = 10

Solution steps

1 - \frac{7}{x - 2} = \frac{7}{x ^{2} - 5 x + 6}

Multiply by LCM

(x - 2) (x - 3) - 7 (x - 3) = 7

Solve

(x - 2) (x - 3) - 7 (x - 3) = 7 : x = 10, x = 2

x = 10, x = 2

Verify Solutions

Find undefined (singularity) points:

x = 2, x = 3

Since the equation is undefined for:

2

x = 10

\frac{0.3}{4} = \frac{9}{y}

\frac{x - 2}{x + 2} = \frac{x + 3}{x - 4}

\frac{8432 - 3870}{x} = 8346

\frac{28}{x - 36} = \frac{36}{x - 28}

\frac{1}{x} + \frac{2}{x - 3} = - \frac{2}{3}

What is the answer to 1-7/(x-2)= 7/(x^2-5x+6) ?
The answer to 1-7/(x-2)= 7/(x^2-5x+6) is x=10
Solve for x: 1-7/(x-2)= 7/(x^2-5x+6)
The solution is x=10