What is the answer to solvefor y, 3/(2xy)= 1/(x^2) ?

The answer to solvefor y, 3/(2xy)= 1/(x^2) is y=(3x)/2 ;\quad x\ne 0

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solvefor y, 3/(2xy)= 1/(x^2)

solve for

y, \frac{3}{2 x y} = \frac{1}{x ^{2}}

y = \frac{3 x}{2}; x \neq = 0

Solution steps

\frac{3}{2 x y} = \frac{1}{x ^{2}}

Cross multiply

3 x^{2} = 2 y x; x \neq = 0

Switch sides

2 y x = 3 x^{2}

Divide both sides by

2 x; x \neq = 0

y = \frac{3 x}{2}; x \neq = 0

y, x - \frac{1}{x} = y - \frac{1}{y}

y, \frac{x}{( y + x )} = \frac{1}{5}

\frac{1}{x} + \frac{1}{x - 15} = \frac{1}{18}

\frac{4}{1600} = \frac{17}{x}

\frac{12}{x} = 4

What is the answer to solvefor y, 3/(2xy)= 1/(x^2) ?
The answer to solvefor y, 3/(2xy)= 1/(x^2) is y=(3x)/2 ;\quad x\ne 0