What is the answer to solvefor t,y=(t-a)/(t+3) ?

The answer to solvefor t,y=(t-a)/(t+3) is t=(-a-3y)/(y-1);\quad y\ne 1

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solvefor t,y=(t-a)/(t+3)

solve for

t, y = \frac{t - a}{t + 3}

t = \frac{- a - 3 y}{y - 1}; y \neq = 1

Solution steps

y = \frac{t - a}{t + 3}

Multiply both sides by

t + 3

y (t + 3) = t - a

Expand

y (t + 3) : t y + 3 y

t y + 3 y = t - a

Move

3 y

to the right side

t y = t - a - 3 y

Move

t

to the left side

t y - t = - a - 3 y

Factor

t y - t : t (y - 1)

t (y - 1) = - a - 3 y

Divide both sides by

y - 1; y \neq = 1

t = \frac{- a - 3 y}{y - 1}; y \neq = 1

2 x - \frac{1}{x} - 1 = 0

y, \frac{3}{3 x + y} = 1

\frac{x - 1}{x} = \frac{x + 1}{x + 3}

\frac{1}{2 k} = \frac{1}{2} - \frac{5}{k}

\frac{x ^{2} - x}{3 x + 1} = \frac{- x}{2 x - 1}

What is the answer to solvefor t,y=(t-a)/(t+3) ?
The answer to solvefor t,y=(t-a)/(t+3) is t=(-a-3y)/(y-1);\quad y\ne 1