What is the answer to 1/(4x^2)= 1/(2x-(\frac{3){4x^2})} ?

The answer to 1/(4x^2)= 1/(2x-(\frac{3){4x^2})} is No Solution

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1/(4x^2)= 1/(2x-(\frac{3){4x^2})}

\frac{1}{4 x ^{2}} = \frac{1}{2 x - ( \frac{3}{4 x ^{2}} )}

No Solution

Solution steps

\frac{1}{4 x ^{2}} = \frac{1}{2 x - ( \frac{3}{4 x ^{2}} )}

Cross multiply

8 x^{3} - 3 = 16 x^{4}

Solve

8 x^{3} - 3 = 16 x^{4} :

No Solution for

x \in R

No Solution

7 - \frac{1}{x} = - 8 x

\frac{3 a}{2 a + 1} - \frac{4}{2 a - 1} = 1

\frac{5}{x} - 2 = \frac{2}{x + 3}

\frac{13}{x} = 10 - x

- \frac{1}{x - 1} + 7 = - \frac{1}{x ^{2} - x}

What is the answer to 1/(4x^2)= 1/(2x-(\frac{3){4x^2})} ?
The answer to 1/(4x^2)= 1/(2x-(\frac{3){4x^2})} is No Solution
Solve for x: 1/(4x^2)= 1/(2x-(\frac{3){4x^2})}
The solution is No Solution