What is the answer to (x^2-9x+20)/(x^2-3x+4)=0 ?

The answer to (x^2-9x+20)/(x^2-3x+4)=0 is x=5,x=4

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(x^2-9x+20)/(x^2-3x+4)=0

\frac{x ^{2} - 9 x + 20}{x ^{2} - 3 x + 4} = 0

x = 5, x = 4

Solution steps

\frac{x ^{2} - 9 x + 20}{x ^{2} - 3 x + 4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 9 x + 20 = 0

Solve

x^{2} - 9 x + 20 = 0 : x = 5, x = 4

x = 5, x = 4

\frac{1}{x - 2} = \frac{1}{2}

\frac{7}{x + 5} = \frac{6}{5}

\frac{- 1}{2 x} = \frac{x - 1}{x - 3}

y, \frac{- 2 x + y}{- x + 2 y} = 0

\frac{x + 1}{x + 2} + \frac{x + 2}{x + 3} = 2

What is the answer to (x^2-9x+20)/(x^2-3x+4)=0 ?
The answer to (x^2-9x+20)/(x^2-3x+4)=0 is x=5,x=4
Solve for x: (x^2-9x+20)/(x^2-3x+4)=0
The solution is x=5,x=4