What is the answer to (2x-2)/(x^2-2x+2)=0 ?

The answer to (2x-2)/(x^2-2x+2)=0 is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2x-2)/(x^2-2x+2)=0

\frac{2 x - 2}{x ^{2} - 2 x + 2} = 0

x = 1

Solution steps

\frac{2 x - 2}{x ^{2} - 2 x + 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x - 2 = 0

Move

2

to the right side

2 x = 2

Divide both sides by

2

x = 1

\frac{7 x + 2}{14 x - 3} = \frac{x - 8}{2 x + 3}

\frac{5}{x + 3} = \frac{3}{x + 5}

5 = \frac{\frac{x}{150}}{\frac{80 - x}{100}}

5.9 \cdot 1 0^{- 2} = \frac{x ^{2}}{0.0288 - x}

\frac{x}{4} - \frac{5}{2 x} = \frac{1}{4 x}

What is the answer to (2x-2)/(x^2-2x+2)=0 ?
The answer to (2x-2)/(x^2-2x+2)=0 is x=1
Solve for x: (2x-2)/(x^2-2x+2)=0
The solution is x=1